为了正常的体验网站,请在浏览器设置里面开启Javascript功能!

第四次试验

2012-07-13 12页 doc 229KB 32阅读

用户头像

is_508264

暂无简介

举报
第四次试验电力电子建模与仿真实验报告(四) 题目:1-Phase, Bipolar-Voltage Switching Inverter Three-Phase PWM Inverter 姓名: 学号: EXAMPLE 12 1-Phase, Bipolar-Voltage Switching Inverter Problems : 1. Obtain the following waveforms using 1Phbsinv: (a) vo and io. (b) vo and id. ...
第四次试验
电力电子建模与仿真实验(四) 题目:1-Phase, Bipolar-Voltage Switching Inverter Three-Phase PWM Inverter 姓名: 学号: EXAMPLE 12 1-Phase, Bipolar-Voltage Switching Inverter Problems : 1. Obtain the following waveforms using 1Phbsinv: (a) vo and io. (b) vo and id. (c) vo, io and po Fig1-1(io and vo) Fig1-2(id and vo) Fig1-3(vo, io and po) 2. Obtain v 01 by means of Fourier analysis of the v o waveform. Compare v 01 with its precalculated nominal value. The Fourier analysis of the vo : DC COMPONENT = -1.367907E+00 HARMONIC FREQUENCY FOURIER NORMALIZED PHASE NORMALIZED NO (HZ) COMPONENT COMPONENT (DEG) PHASE (DEG) 1 4.000E+01 2.152E+02 1.000E+00 1.444E+02 0.000E+00 2 8.000E+01 8.203E-01 3.811E-03 6.700E+00 -2.821E+02 3 1.200E+02 1.088E+00 5.054E-03 1.356E+02 -2.976E+02 4 1.600E+02 6.913E-01 3.212E-03 -1.541E+02 -7.317E+02 5 2.000E+02 5.708E-01 2.652E-03 -9.746E+01 -8.195E+02 6 2.400E+02 6.413E-01 2.980E-03 1.581E+02 -7.083E+02 7 2.800E+02 9.704E-01 4.509E-03 1.783E+02 -8.325E+02 8 3.200E+02 1.027E+00 4.771E-03 -4.752E+01 -1.203E+03 9 3.600E+02 1.233E+00 5.730E-03 8.358E+01 -1.216E+03 10 4.000E+02 1.536E+00 7.138E-03 3.865E+01 -1.405E+03 11 4.400E+02 6.210E-01 2.885E-03 -1.606E+02 -1.749E+03 12 4.800E+02 3.179E-01 1.477E-03 1.087E+02 -1.624E+03 13 5.200E+02 1.612E+00 7.491E-03 5.246E+01 -1.825E+03 14 5.600E+02 1.071E+00 4.974E-03 -8.479E+01 -2.106E+03 15 6.000E+02 2.222E-01 1.033E-03 7.063E+01 -2.095E+03 16 6.400E+02 1.067E+00 4.956E-03 2.316E+01 -2.287E+03 17 6.800E+02 6.656E-01 3.092E-03 -1.299E+01 -2.468E+03 18 7.200E+02 1.167E+00 5.424E-03 1.339E+02 -2.465E+03 19 7.600E+02 8.236E-01 3.827E-03 -1.529E+02 -2.897E+03 20 8.000E+02 1.060E+00 4.923E-03 1.143E+02 -2.774E+03 21 8.400E+02 2.719E+00 1.263E-02 -1.453E+02 -3.178E+03 22 8.800E+02 3.026E-01 1.406E-03 -1.157E+02 -3.292E+03 23 9.200E+02 5.888E+01 2.735E-01 1.622E+02 -3.159E+03 TOTAL HARMONIC DISTORTION = 2.745433E+01 PERCENT From the Fourier analysis, we know 152.17V Because Vo1(rms) = 153.33 V ,so Vo1 approximately equals to the nominal value of Vo1(rms). 3. Using the results of Problem 2, obtain the ripple component v ripple waveform in the output voltage. the ripple component vripple = vo- vo1=[ v(L1:1)-v(V5:-)]-Vo1 Fig3-1(vo- vo1) 4. Obtain i01 by means of Fourier analysis of the i o waveform. Compare i 01 with its precalculated nominal value. FOURIER COMPONENTS OF TRANSIENT RESPONSE I(L_L1) DC COMPONENT = -4.341032E-01 HARMONIC FREQUENCY FOURIER NORMALIZED PHASE NORMALIZED NO (HZ) COMPONENT COMPONENT (DEG) PHASE (DEG) 1 4.000E+01 1.359E+01 1.000E+00 -2.799E+01 0.000E+00 2 8.000E+01 1.007E-02 7.413E-04 7.046E+01 1.264E+02 3 1.200E+02 6.720E-02 4.946E-03 4.604E+01 1.300E+02 4 1.600E+02 9.693E-03 7.135E-04 -6.629E+01 4.565E+01 5 2.000E+02 2.342E-02 1.724E-03 -7.893E+01 6.100E+01 6 2.400E+02 6.280E-03 4.623E-04 2.867E+01 1.966E+02 7 2.800E+02 7.838E-03 5.770E-04 -1.259E+02 7.001E+01 8 3.200E+02 5.757E-03 4.238E-04 -1.743E+02 4.955E+01 9 3.600E+02 2.774E-03 2.042E-04 1.070E+02 3.589E+02 10 4.000E+02 8.593E-03 6.326E-04 -7.327E+01 2.066E+02 11 4.400E+02 7.374E-03 5.428E-04 5.145E+01 3.593E+02 12 4.800E+02 3.456E-03 2.544E-04 -3.619E+01 2.996E+02 13 5.200E+02 1.061E-02 7.814E-04 -1.133E+02 2.505E+02 14 5.600E+02 5.217E-03 3.840E-04 -4.503E+01 3.468E+02 15 6.000E+02 3.839E-03 2.826E-04 -8.663E+01 3.331E+02 16 6.400E+02 2.546E-03 1.874E-04 -1.618E+02 2.860E+02 17 6.800E+02 1.683E-03 1.239E-04 -5.285E+01 4.229E+02 18 7.200E+02 4.983E-03 3.668E-04 -7.910E+01 4.246E+02 19 7.600E+02 1.790E-03 1.318E-04 -8.766E+01 4.441E+02 20 8.000E+02 2.168E-03 1.596E-04 5.595E+00 5.653E+02 21 8.400E+02 3.123E-02 2.299E-03 1.066E+00 5.888E+02 22 8.800E+02 2.108E-03 1.551E-04 1.617E+02 7.774E+02 23 9.200E+02 1.028E+00 7.570E-02 2.208E+00 6.459E+02 TOTAL HARMONIC DISTORTION = 7.593596E+00 PERCENT According to the Fourier analysis, We know that its precalculated nominal value Io1(rms) = 10 A So Io1 approximately equals to the nominal value of Io1(rms) 5. Using the results of Problem 4, obtain the ripple component i ripple in the output current. From the problem 4,we know THD=7.59% ,I01=13.59 So 6. Obtain Id(avg) and id2 (the component at the 2nd harmonic frequency) by means of the Fourier analysis of the id waveform. Compare them with their precalculated nominal values FOURIER COMPONENTS OF TRANSIENT RESPONSE I(V_V1) DC COMPONENT = -4.908958E+00 HARMONIC FREQUENCY FOURIER NORMALIZED PHASE NORMALIZED NO (HZ) COMPONENT COMPONENT (DEG) PHASE (DEG) 1 4.000E+01 4.289E-01 1.000E+00 -1.946E+00 0.000E+00 2 8.000E+01 5.451E+00 1.271E+01 6.056E+01 6.445E+01 3 1.200E+02 4.544E-02 1.060E-01 -1.795E+02 -1.736E+02 4 1.600E+02 7.639E-02 1.781E-01 1.319E+02 1.396E+02 5 2.000E+02 3.974E-02 9.267E-02 -1.334E+01 -3.614E+00 6 2.400E+02 3.045E-02 7.100E-02 -8.175E+01 -7.007E+01 7 2.800E+02 4.784E-02 1.116E-01 9.565E+01 1.093E+02 8 3.200E+02 4.988E-02 1.163E-01 -1.385E+02 -1.229E+02 9 3.600E+02 3.620E-02 8.441E-02 -9.852E+01 -8.100E+01 10 4.000E+02 5.078E-02 1.184E-01 -8.064E+01 -6.118E+01 11 4.400E+02 4.159E-02 9.697E-02 1.219E+02 1.433E+02 12 4.800E+02 1.063E-02 2.479E-02 -6.397E+01 -4.062E+01 13 5.200E+02 4.512E-02 1.052E-01 -2.976E+01 -4.464E+00 14 5.600E+02 2.213E-02 5.160E-02 -3.340E+01 -6.157E+00 15 6.000E+02 3.584E-02 8.358E-02 1.738E+02 2.030E+02 16 6.400E+02 4.414E-02 1.029E-01 -3.200E+01 -8.660E-01 17 6.800E+02 4.462E-02 1.040E-01 7.998E-01 3.388E+01 18 7.200E+02 5.566E-02 1.298E-01 5.333E+01 8.835E+01 19 7.600E+02 3.212E-02 7.489E-02 1.077E+02 1.447E+02 20 8.000E+02 1.147E-01 2.674E-01 7.242E+00 4.616E+01 21 8.400E+02 2.905E-02 6.773E-02 -8.042E+01 -3.956E+01 22 8.800E+02 1.266E+00 2.952E+00 7.332E+00 5.014E+01 23 9.200E+02 1.661E-01 3.873E-01 9.427E+01 1.390E+02 TOTAL HARMONIC DISTORTION = 1.306384E+03 PERCENT From the Fourier analysis, we know : Id=-DC= 4.91A① ② Vd = ,cos So: ③ ④ ①≈③, ②≈④ So Id and Id2 approximately equal to their precalculated nominal values 7. Using the results of Problem 6, obtain the high frequency ripple component id,ripple in the input dc current. Calculate its rms value. From Problem 6,we know THD=13.06 So =13.06*0.43=5.62A RMS 5.62/1.414=3.97 EXAMPLE 16 Three-Phase PWM Inverter Problems 1. Obtain the following waveforms using : (a) vAN and iA. (b) vAn and iA. (c) vAN and id. Fig 1-1 ( vAN and iA ) Fig 1-2 ( vAn and iA ) Fig1-3(vAN and id ) 2. Obtain vAn1 by means of Fourier analysis of the vAn waveform. Compare vAn1 with its precalculated nominal value. The Fourier analysis of the vAn is: DC COMPONENT = -2.239930E-02 HARMONIC FREQUENCY FOURIER NORMALIZED PHASE NORMALIZED NO (HZ) COMPONENT COMPONENT (DEG) PHASE (DEG) 1 4.762E+01 1.491E+02 1.000E+00 1.372E+02 0.000E+00 2 9.524E+01 4.832E-01 3.240E-03 -8.232E+01 -3.568E+02 3 1.429E+02 4.600E-02 3.085E-04 -1.106E+02 -5.222E+02 4 1.905E+02 4.246E-01 2.848E-03 1.929E+01 -5.296E+02 5 2.381E+02 6.052E-01 4.059E-03 3.124E+00 -6.830E+02 6 2.857E+02 4.407E-02 2.955E-04 -1.323E+02 -9.557E+02 7 3.333E+02 7.786E-01 5.222E-03 1.476E+02 -8.130E+02 8 3.810E+02 6.795E-01 4.557E-03 1.786E+02 -9.192E+02 9 4.286E+02 4.730E-02 3.172E-04 -1.491E+02 -1.384E+03 10 4.762E+02 9.098E-01 6.101E-03 1.662E+02 -1.206E+03 11 5.238E+02 1.551E-01 1.040E-03 -7.099E+01 -1.580E+03 12 5.714E+02 4.816E-02 3.230E-04 -1.729E+02 -1.820E+03 13 6.190E+02 1.455E+00 9.758E-03 1.256E+02 -1.658E+03 14 6.667E+02 8.385E-01 5.623E-03 -9.956E+01 -2.021E+03 15 7.143E+02 4.384E-02 2.940E-04 1.718E+02 -1.887E+03 16 7.619E+02 2.030E-01 1.361E-03 -9.822E+01 -2.294E+03 17 8.095E+02 1.799E+00 1.207E-02 -9.840E+01 -2.431E+03 18 8.571E+02 4.842E-02 3.247E-04 1.518E+02 -2.318E+03 19 9.048E+02 4.585E+01 3.075E-01 1.751E+02 -2.432E+03 20 9.524E+02 7.544E-01 5.059E-03 7.145E+01 -2.673E+03 21 1.000E+03 4.487E-02 3.009E-04 1.273E+02 -2.754E+03 22 1.048E+03 6.855E-01 4.597E-03 1.205E+02 -2.898E+03 23 1.095E+03 4.598E+01 3.084E-01 4.126E+00 -3.152E+03 TOTAL HARMONIC DISTORTION = 4.359678E+01 PERCENT From Fourier analysis ,we know: precalculated nominal value :VAn1=105.39V the VAn1 equals to its precalculated nominal value. 3. Using the results of Problem 2, obtain the ripple component vripple waveform in the output voltage. vripple = VAn- VAn1= [v(L1:1)-v(V5:-)]- 105.6* 4.Obtain iA1 by means of Fourier analysis of iA waveform. Compare iA1 with its precalculated nominal value. FOURIER COMPONENTS OF TRANSIENT RESPONSE I(L_L1) DC COMPONENT = -1.633990E-02 HARMONIC FREQUENCY FOURIER NORMALIZED PHASE NORMALIZED NO (HZ) COMPONENT COMPONENT (DEG) PHASE (DEG) 1 4.762E+01 1.417E+01 1.000E+00 1.076E+02 0.000E+00 2 9.524E+01 1.690E-02 1.193E-03 -1.546E+02 -3.698E+02 3 1.429E+02 8.724E-03 6.157E-04 1.718E+02 -1.510E+02 4 1.905E+02 7.686E-03 5.424E-04 1.213E+02 -3.090E+02 5 2.381E+02 1.073E-02 7.575E-04 -1.011E+02 -6.390E+02 6 2.857E+02 3.529E-03 2.491E-04 1.441E+02 -5.014E+02 7 3.333E+02 4.672E-03 3.297E-04 3.532E+01 -7.177E+02 8 3.810E+02 5.291E-03 3.734E-04 1.213E+02 -7.393E+02 9 4.286E+02 2.874E-03 2.028E-04 1.227E+02 -8.455E+02 10 4.762E+02 6.673E-03 4.709E-04 1.030E+02 -9.728E+02 11 5.238E+02 7.769E-03 5.483E-04 9.967E+01 -1.084E+03 12 5.714E+02 1.698E-03 1.198E-04 1.012E+02 -1.190E+03 13 6.190E+02 6.125E-03 4.322E-04 7.720E+01 -1.321E+03 14 6.667E+02 1.612E-03 1.137E-04 1.249E+02 -1.381E+03 15 7.143E+02 1.685E-03 1.189E-04 8.254E+01 -1.531E+03 16 7.619E+02 2.819E-03 1.990E-04 1.944E+00 -1.719E+03 17 8.095E+02 4.433E-02 3.129E-03 1.731E+02 -1.656E+03 18 8.571E+02 1.128E-03 7.959E-05 6.326E+01 -1.873E+03 19 9.048E+02 8.088E-01 5.708E-02 8.755E+01 -1.957E+03 20 9.524E+02 9.749E-03 6.880E-04 -3.756E+01 -2.189E+03 21 1.000E+03 1.190E-03 8.397E-05 4.404E+01 -2.215E+03 22 1.048E+03 1.136E-02 8.015E-04 4.363E+01 -2.323E+03 23 1.095E+03 6.660E-01 4.700E-02 -8.389E+01 -2.558E+03 TOTAL HARMONIC DISTORTION = 7.403818E+00 PERCENT We can learn that We know that precalculated nominal value of IA1=10A So IA1 equals to its precalculated nominal value 5. Using the results of Problem 4, obtain the ripple component iripple in the output current. From the problem 4,we know THD=7.4%, so we can get that: 6.Obtain Id(avg) by means of Fourier analysis and obtain the high frequency ripple id,ripple = id - Id(avg) in the input current. The Fourier analysis of the iv1 is as follows: DC COMPONENT = -8.787830E+00 HARMONIC FREQUENCY FOURIER NORMALIZED PHASE NORMALIZED NO (HZ) COMPONENT COMPONENT (DEG) PHASE (DEG) 1 4.762E+01 1.441E-02 1.000E+00 1.634E+02 0.000E+00 2 9.524E+01 1.172E-02 8.135E-01 2.644E+01 -3.004E+02 3 1.429E+02 5.315E-02 3.689E+00 1.406E+02 -3.497E+02 4 1.905E+02 6.418E-03 4.454E-01 7.955E+01 -5.742E+02 5 2.381E+02 7.029E-03 4.879E-01 -1.301E+01 -8.302E+02 6 2.857E+02 4.560E-02 3.165E+00 -1.116E+02 -1.092E+03 7 3.333E+02 5.715E-03 3.967E-01 7.054E+01 -1.073E+03 8 3.810E+02 6.181E-03 4.290E-01 -2.357E+01 -1.331E+03 9 4.286E+02 9.775E-02 6.784E+00 -1.723E+01 -1.488E+03 10 4.762E+02 5.177E-03 3.593E-01 5.656E+01 -1.578E+03 11 5.238E+02 5.693E-03 3.951E-01 -4.294E+01 -1.841E+03 12 5.714E+02 9.631E-02 6.684E+00 -7.650E+01 -2.038E+03 13 6.190E+02 5.416E-03 3.759E-01 3.786E+01 -2.087E+03 14 6.667E+02 5.940E-03 4.123E-01 -6.016E+01 -2.348E+03 15 7.143E+02 6.415E-02 4.452E+00 8.983E+01 -2.362E+03 16 7.619E+02 5.151E-03 3.575E-01 1.546E+01 -2.599E+03 17 8.095E+02 5.751E-03 3.992E-01 -9.197E+01 -2.870E+03 18 8.571E+02 2.787E+00 1.934E+02 -3.141E+01 -2.973E+03 19 9.048E+02 2.586E-03 1.794E-01 -7.696E+01 -3.182E+03 20 9.524E+02 2.128E-03 1.477E-01 -9.392E+01 -3.363E+03 21 1.000E+03 9.176E-02 6.369E+00 -9.376E+01 -3.526E+03 22 1.048E+03 5.374E-03 3.730E-01 2.560E+01 -3.570E+03 23 1.095E+03 8.048E-03 5.586E-01 -7.191E+01 -3.831E+03 TOTAL HARMONIC DISTORTION = 1.939046E+04 PERCENT Id(avg)=-DC=8.79A 7. Obtain the load neutral voltage with respect to the mid-point of the dc input voltage. PAGE 4 _1400091994.unknown _1400092536.unknown _1400093886.unknown _1400094155.unknown _1400094344.unknown _1400094513.unknown _1400093981.unknown _1400093134.unknown _1400093227.unknown _1400092919.unknown _1400092443.unknown _1400092472.unknown _1400092382.unknown _1400091646.unknown _1400091870.unknown _1399914080.unknown _1400091029.unknown _1399913980.unknown _1399867236.unknown
/
本文档为【第四次试验】,请使用软件OFFICE或WPS软件打开。作品中的文字与图均可以修改和编辑, 图片更改请在作品中右键图片并更换,文字修改请直接点击文字进行修改,也可以新增和删除文档中的内容。
[版权声明] 本站所有资料为用户分享产生,若发现您的权利被侵害,请联系客服邮件isharekefu@iask.cn,我们尽快处理。 本作品所展示的图片、画像、字体、音乐的版权可能需版权方额外授权,请谨慎使用。 网站提供的党政主题相关内容(国旗、国徽、党徽..)目的在于配合国家政策宣传,仅限个人学习分享使用,禁止用于任何广告和商用目的。

历史搜索

    清空历史搜索