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能量单位换算公式

2012-07-21 1页 pdf 100KB 122阅读

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能量单位换算公式 TYPICAL CONVERSION FORMULAS LOG -> LINEAR VOLTAGE FIELD STRENGTH & POWER DENSITY dBµV to Volts V = 10 ((dBµV – 120) / 20) dBµV/m to V/m V/m = 10 (((dBµV/m) -120) / 20) Volts to dBµV dBµV = 20 log(V) + 120 V/m to dBµV/m dBµV/m = 20 log(V/m) + 120 dBV to Volts V = ...
能量单位换算公式
TYPICAL CONVERSION FORMULAS LOG -> LINEAR VOLTAGE FIELD STRENGTH & POWER DENSITY dBµV to Volts V = 10 ((dBµV – 120) / 20) dBµV/m to V/m V/m = 10 (((dBµV/m) -120) / 20) Volts to dBµV dBµV = 20 log(V) + 120 V/m to dBµV/m dBµV/m = 20 log(V/m) + 120 dBV to Volts V = 10 (dBV / 20) dBµV/m to dBmW/m2 dBmW/m2 = dBµV/m – 115.8 Volts to dBV dBV = 20log(V) dBmW/m2 to dBµV/m dBµV/m = dBmW/m2 + 115.8 dBV to dBµV dBµV = dBV +120 dBµV/m to dBµA/m dBµA/m = dBµV/m – 51.5 dBµV to dBV dBV = dBµV - 120 dBµA/m to dBµV/m dBµV/m = dBµA + 51.5 LOG -> LINEAR CURRENT dBµA/m to dBpT DBpT = dBµA/m + 2 dBµA to uA µA = 10 (dBµA / 20) dBpT to dBµA/m dBµA/m = dBpT – 2 µA to dBµA dBµA = 20 log(µA) W/m2 to V/m V/m = SQRT(W/m2 * 377) dBA to A A = 10 (dBA / 20) V/m to W/m2 W/m2 = (V/m)2 / 377 A to dBA dBA = 20log(A) µT to A/m A/m = µT / 1.25 dBA to dBµA dBµA = dBA + 120 A/m to µT µT = 1.25 * A/m dBµA to dBA dBA = dBµA -120 E-FIELD ANTENNAS LOG -> LINEAR POWER Correction Factor dBµV/m = dBµV + AF dBm to Watts W = 10((dBm – 30)/10) Field Strength V/m = 30 * watts * Gain numeric meters Watts to dBm dBm = 10log(W) + 30 Required Power Watts = (V/m * meters)2 30 * Gain numeric dBW to Watts W = 10(dBW / 10) Watts to dBW dBW = 10log(W) LOOP ANTENNAS dBW to dBm dBm = dBW + 30 Correction Factors dBµA/m = dBµV + AF dBm to dBW dBW = dBm - 30 Assumed E-field for shielded loops dBµV/m = dBµA/m + 51.5 TERM CONVERSIONS dBpT = dBµV + dBpT/µV dBm to dBµV dBµV = dBm + 107 (50Ω) dBµV = dBm + 10log(Z) + 90 CURRENT PROBES dBµV to dBm dBm = dBµV – 107 (50Ω) dBm = dBµV – 10log(Z) – 90 Correction Factor dBµA = dBµV – dB(ohm) dBm to dBµA dBµA = dBm + 73 (50Ω) dBµA = dBm – 10log(Z) + 90 Power needed for injection probe given voltage(V) into 50Ω load and Probe Insertion Loss (IL) dBµA to dBm dBm = dBµA – 73 (50Ω) dBm = dBµA + 10log(Z) – 90 Watts = 10 ((IL + 10log(V2/50))/10) dBµA to dBµV dBµV = dBµA + 34 (50Ω) dBµV = dBµA + 20log(Z) dBµV to dBµA dBµA = dBµV – 34 (50Ω) dBµA = dBµV – 20log(Z) LOG -> LINEAR VOLTAGE FIELD STRENGTH & POWER DENSITY LOG -> LINEAR CURRENT E-FIELD ANTENNAS TERM CONVERSIONS CURRENT PROBES
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